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I gave up entirely on finding the player by name. Instead of looking for window.as or window.AudioSource, I simply staked out the exit. I hooked the most generic, lowest-level method available:
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// 易错点4:栈空时返回1而非i+1 → 仅i=0时正确,i0时(如i=3)会返回1而非4
It follows a 2025 report by the Cambridgeshire Poverty Strategy Commission that recommended helping low-income households to receive all the help they should.